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question:"x=2" is a ( ) condition for "(x+1)(x-2)=0".A: Sufficient but not necessaryB: Necessary but not sufficientC: Sufficient conditionD: Neither sufficient nor necessary

answer:Since "x=2" implies "(x+1)(x-2)=0", and "(x+1)(x-2)=0" implies "x=2 or x=-1", therefore, "x=2" is a sufficient but not necessary condition for "(x+1)(x-2)=0". Hence, the correct choice is boxed{A}.

question:Among the following propositions:① The necessary and sufficient condition for the complex numbers a+bi and c+di to be equal is a=c and b=d.② It is impossible to compare the magnitude of any complex number.③ If overrightarrow {z_{1}} = overrightarrow {z_{2}}, then | overrightarrow {z_{1}} | = | overrightarrow {z_{2}} |.④ If | overrightarrow {z_{1}} | = | overrightarrow {z_{2}} |, then overrightarrow {z_{1}} = overrightarrow {z_{2}} or overrightarrow {z_{1}} = - overrightarrow {z_{2}}.The number of incorrect propositions is (  ).A. 1B. 2C. 3D. 4

answer:Let's analyze each proposition individually:① For complex numbers a+bi and c+di to be equal, we must have a+bi = c+di. This equality holds if and only if a=c and b=d. Proposition ① is therefore correct.② Saying that the magnitudes of any complex number cannot be compared is incorrect. While it is true that there is no natural ordering for complex numbers, real numbers (a subset of complex numbers) can indeed be compared. Thus, proposition ② is incorrect.③ If overrightarrow {z_{1}} = overrightarrow {z_{2}}, then by definition of vector equality, every component of overrightarrow {z_{1}} must be equal to the corresponding component of overrightarrow {z_{2}}. This implies that the magnitudes, or the modulus, of those complex numbers are equal. Therefore, the statement | overrightarrow {z_{1}} | = | overrightarrow {z_{2}} | is correct, making proposition ③ correct.④ If | overrightarrow {z_{1}} | = | overrightarrow {z_{2}} |, this implies that the two complex numbers have the same magnitude. However, this condition alone does not guarantee that the vectors themselves are equal or negatives of each other. There are infinitely many complex numbers with the same magnitude but different arguments (i.e., they are not co-linear). Hence, proposition ④ is incorrect.In conclusion, there are two incorrect propositions, ② and ④.The correct answer is boxed{B}.

question:Given the complex number z=(2-i)^2 (where i is the imaginary unit), find the modulus of z.

answer:First, we calculate z=(2-i)^2. According to the rules of complex numbers, we have:z=(2-i)^2=2^2-2times2i+i^2=4-4i+(-1)=3-4i.Next, we find the modulus of z. The modulus of a complex number a+bi is given by sqrt{a^2+b^2}. Therefore, the modulus of z=3-4i is:|z|=sqrt{3^2+(-4)^2}=sqrt{9+16}=sqrt{25}=5.So, the answer is: boxed{5}.To solve this problem, we used the rules of complex number arithmetic to simplify the given expression. Then, we applied the formula for the modulus of a complex number to find the required value. This problem primarily tests the ability to calculate the modulus of a complex number and to simplify complex expressions using the rules of complex number arithmetic.

question:How long will the strip be if a cubic kilometer is cut into cubic meters and laid out in a single line?#

answer:In one cubic kilometer - a billion cubic meters.## SolutionIn one cubic kilometer, there is a billion cubic meters (1000 in length, 1000 in width, and 1000 in height). If all of them are laid out in a row, it would form a strip one billion meters long, i.e., one million kilometers.## Answer1000000 km.

question:3.1. Five identical squares, standing in a row, were cut by two horizontal lines. The sum of the perimeters of the resulting 15 rectangles is 800 cm. Indicate in centimeters the length of the original squares.| | | | | || :--- | :--- | :--- | :--- | :--- || | | | | |

answer:# Answer: 20Solution. Let's calculate how many times the side of the original square is repeated in the sum of all perimeters. The sides of the rectangle are counted once (a total of 12), and the crossbars are counted twice (4 cdot 2 + 10 cdot 2 = 28). In total, 40.800: 40=20 cm - the side of the square.

question:Given that a > b > c > 0, x= sqrt {a^{2}+(b+c)^{2}}, y= sqrt {b^{2}+(c+a)^{2}}, z= sqrt {c^{2}+(a+b)^{2}}, determine the order of magnitude of x, y, and z.

answer:Since a > b > c > 0,We have 2ab > 2ac > 2bc,Now, let's simplify x, y, and z:x = sqrt {a^{2}+(b+c)^{2}} = sqrt {a^{2}+b^{2}+c^{2}+2bc},y = sqrt {b^{2}+(c+a)^{2}} = sqrt {a^{2}+b^{2}+c^{2}+2ac},z = sqrt {c^{2}+(a+b)^{2}} = sqrt {a^{2}+b^{2}+c^{2}+2ab},Hence, z > y > x.So, the answer is: boxed{z > y > x}.This is because a > b > c > 0 implies 2ab > 2ac > 2bc. Substituting these values into the expressions for x, y, and z gives us the result.This problem tests understanding of the properties of inequalities and the application of the multiplication formula, requiring both reasoning and computational skills. It is a basic-level problem.

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